\[\alpha -x\] graph of body is
A)
B)
C)
D)
Correct Answer: A
Solution :
| From \[\upsilon -x\]graph, equation is |
| \[\upsilon =\frac{-{{\upsilon }_{0}}}{{{x}_{0}}}.x+{{\upsilon }_{0}}\] |
| Differentiating w.r.t. t, we get |
| \[a=\frac{-{{\upsilon }_{0}}}{{{x}_{0}}}.\upsilon =\frac{-{{\upsilon }_{0}}}{{{x}_{0}}}\left( -\frac{{{\upsilon }_{0}}}{{{x}_{0}}}.x+{{\upsilon }_{0}} \right)\] |
| \[\Rightarrow \,\,\,\,\,\,\,\,a=\frac{\upsilon _{0}^{2}}{x_{0}^{2}}.x-\frac{\upsilon _{0}^{2}}{{{x}_{0}}}\] |
| [Positive slope and negative intercept] |
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