A) (3, 4)
B) (2, 2)
C) (4, 3)
D) (4, 4)
Correct Answer: B
Solution :
\[I=\left( \frac{a{{x}_{1}}+b{{x}_{2}}+c{{x}_{3}}}{a+b+c},\frac{a{{y}_{1}}+b{{y}_{2}}+c{{y}_{2}}}{a+b+c} \right)\] |
\[=\left( \frac{8(60)+6(0)+10(0)}{24},\frac{10(0)+6(8)+8(0)}{24} \right)\] |
\[=(2,2).\] |
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