A) 2
B) \[-\,4\]
C) 4
D) 6
Correct Answer: C
Solution :
Let \[b=ar,\]\[c=a{{r}^{2}}\] |
\[x=\frac{a\,\,(1+r)}{2}\] |
\[y=\frac{ar\,\,(1+r)}{2}\] |
\[\left( \frac{a}{x}+\frac{c}{y} \right)\,\,\left( \frac{b}{x}+\frac{b}{y} \right)=\left\{ \frac{a\,\,\times \,\,2}{a\,\,(1\,\,+\,\,r)}+\frac{a{{r}^{2}}\,\,\times \,\,2}{ar\,\,(1\,\,+\,\,r)} \right\}\] |
\[\left\{ \frac{ar\,\,\times \,\,2}{a\,\,(1\,\,+\,\,r)}+\frac{ar\,\,\times \,\,2}{ar\,\,(1+r)} \right\}\] |
\[=\left\{ \frac{2}{1+r}+\frac{2r}{1+r} \right\}\,\,\left\{ \frac{2r}{1+r}+\frac{2}{1+r} \right\}=4\] |
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