A) c
B) 2c
C) 3c
D) 5c
Correct Answer: B
Solution :
Given \[f\,\,(x+c)=1+{{[{{(1-f\,\,(x))}^{5}}]}^{1/5}}\] |
\[\Rightarrow f\,\,(x+c)=1+[\,1-f\,\,(x)]\] |
\[\Rightarrow f\,\,(x+2c)=1+[1-f\,\,(x+c)]\] |
\[=1+[\,1-1-1+f\,\,(x)]\] |
\[=1+f\,\,(x)-1=f\,\,(\,x+2c)=f\,\,(x)\] |
Hence f(x) is a periodic function of period 2c. |
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