A) \[{{v}_{s}}=22km\,{{s}^{-1}}\]
B) \[{{v}_{s}}=42km\,{{s}^{-1}}\]
C) \[{{v}_{s}}=62km\,{{s}^{-1}}\]
D) \[{{v}_{s}}=72km\,{{s}^{-1}}\]
Correct Answer: B
Solution :
\[\frac{1}{2}mV_{e}^{2}-\frac{G{{M}_{e}}m}{{{R}_{e}}}-\frac{G{{M}_{e}}m\times 3\times {{10}^{5}}}{2.5\times {{10}^{4}}{{R}_{e}}}=0\] \[\frac{V_{e}^{2}}{2}=\frac{G{{M}_{e}}}{{{R}_{e}}}\left[ 1+\frac{3\times {{10}^{5}}}{2.5\times {{10}^{4}}} \right]\]\[{{v}_{e}}=\sqrt{13\left( \frac{2G{{M}_{e}}}{{{R}_{e}}} \right)}=\sqrt{13}\times 11.2\approx 42\]You need to login to perform this action.
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