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KVPY Sample Paper KVPY Stream-SX Model Paper-8

  • question_answer
    The ground state energy of hydrogen atom is \[-13.6eV.\] The energy of second excited state of \[H{{e}^{+}}\] ion in \[eV\] is:

    A) \[-54.4\]                        

    B) \[-3.4\]

    C) \[-6.04\]                        

    D) \[-27.2\]

    Correct Answer: C

    Solution :

    \[E=-13.6\frac{{{n}^{2}}}{{{z}^{2}}}eV\] \[E_{He}^{+}=-13.6\frac{4}{9}.\]


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