A) \[\frac{-h}{eE{{t}^{2}}}\]
B) \[\frac{-eht}{E}\]
C) \[\frac{-mh}{eE{{t}^{2}}}\]
D) \[\frac{-h}{eE}\]
Correct Answer: A
Solution :
Acceleration, \[a=\frac{Ee}{m}\] |
Velocity of electron, \[v=at\,=\frac{Eet}{m}\] |
Wavelength,\[\lambda =\frac{h}{mv}=\frac{h}{Eet}\] |
Now \[\frac{d\lambda }{dt}=-\frac{h}{eE{{t}^{2}}}\] |
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