A) 400
B) 300
C) 200
D) 150
Correct Answer: C
Solution :
\[N={{N}_{0}}{{e}^{-\lambda t}}\] |
Or \[100\,\,\,\,=1600{{e}^{-\lambda \times 8}}..\left( i \right)\] |
and \[N\,\,\,\,\,=1600{{e}^{-\lambda \times 6}}..\left( \operatorname{ii} \right)\] |
(ii)/(i), we have |
\[\frac{N}{100}\,\,\,\,=\,\,\,\,\,{{e}^{\left( -6\lambda +9\lambda \right)}}\] |
\[\,=\,\,\,\,{{e}^{+2\lambda }}\,\,..\left( \operatorname{iii} \right)\] |
Now from equation (i) and (iii), we get \[\frac{N}{100}\,\,\,\,=\,\,\,\,2\] |
\[N\,\,\,\,\,=\,\,\,\,200.\] |
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