KVPY Sample Paper KVPY Stream-SX Model Paper-9

  • question_answer
    Electrode potential for \[Zn\] electrode varies according to the equation. \[{{E}_{Z{{n}^{2+}}|Zn}}=E{{{}^\circ }_{Z{{n}^{2+}}|Zn}}-\frac{0.059}{2}\log \frac{1}{[Z{{n}^{2+}}]}.\] The graph of \[{{E}_{Z{{n}^{2+}}|Zn}}\] vs log \[[Z{{n}^{2+}}]\] is-

    A)

    B)

    C)

    D)

    Correct Answer: B

    Solution :

    \[{{E}_{Z{{n}^{2+}}\left| Zn \right.}}E_{Z{{n}^{2+}}\left| Zn \right.}^{{}^\circ }+\frac{0.059}{2}\log [Z{{n}^{+2}}]\] Comparing with \[y=mx+c,\] graph between \[{{E}_{Z{{n}^{2+}}\left| Zn \right.}}\] and \[\log [Z{{n}^{2+}}]\] and is a straight line with positive slope and positive intercept.


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