A) \[Co,\,\,Z=27\]
B) \[lron,\,\,Z=26\]
C) \[Mn,\,\,Z=25\]
D) \[Ni,\,\,Z=28\]
Correct Answer: A
Solution :
\[\frac{1}{{{\lambda }_{\alpha }}}=\frac{3R}{4}{{(Z-1)}^{2}}\] \[\Rightarrow \] \[(Z-1)=\sqrt{\frac{4}{3R{{\lambda }_{\alpha }}}}=\sqrt{\frac{4}{3\times 1.1\times {{10}^{7}}\times 1.8\times {{10}^{-10}}}}\] \[\Rightarrow \] \[\frac{200}{3}\sqrt{\frac{5}{33}}=\frac{78}{3}=26.\]\[\Rightarrow \]\[Z=27\]
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