A) 0.12 g
B) 0.21 g
C) 0.252 g
D) 0.3 g
Correct Answer: C
Solution :
Let x gm\[Ca{{C}_{24}}\] |
\[Ca{{C}_{2}}{{O}_{4}}\xrightarrow{\Delta }CaC{{O}_{3}}\xrightarrow{\Delta }CaO\] |
\[\begin{matrix} \frac{x}{128}mole & \frac{x}{128}mole & \frac{x}{128}mole \\ \end{matrix}\] |
Let \[0.6-x\,\,gm\,\,Mg{{C}_{2}}{{O}_{4}}\] |
\[Mg{{C}_{2}}{{O}_{4}}\xrightarrow{\Delta }MgC{{O}_{3}}\xrightarrow{\Delta }MgO\] |
\[\begin{matrix} \frac{0.6-x}{112}mole & \frac{0.6-x}{112}mole & \frac{0.6-x}{112}mole \\ \end{matrix}\] |
[A] |
Weight of \[CaO+MgO\] |
\[=\frac{0.48}{128}\,\,\times \,\,56+\frac{0.12}{112}\,\,\times \,\,40=0.252\,\,gm\] |
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