A) \[P({{\omega }_{1}})=\frac{1}{2},P({{\omega }_{2}})=\frac{1}{3},P({{\omega }_{3}})=\frac{2}{3}\]
B) \[P({{\omega }_{1}})=\frac{1}{2},P({{\omega }_{2}})=\frac{1}{3},P({{\omega }_{3}})=\frac{1}{4}\]
C) \[P({{\omega }_{1}})=\frac{1}{2},P({{\omega }_{2}})=\frac{1}{3},P({{\omega }_{3}})=\frac{-1}{6}\]
D) \[P({{\omega }_{1}})=\frac{1}{2},P({{\omega }_{2}})=\frac{1}{3},P({{\omega }_{3}})=\frac{1}{6}\]
Correct Answer: D
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