A) \[f(A\cup B)=f(A)\cup f(B)\]
B) \[f(A\cap B)=f(A)\cap f(B)\]
C) \[{{f}^{-1}}(C\cup D)={{f}^{-1}}(C)\cup {{f}^{-1}}(D)\]
D) \[{{f}^{-1}}(C\,\cap D)={{f}^{-1}}(C)\cap {{f}^{-1}}(D)\]
Correct Answer: B
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