question_answer

The points \[\left( -\text{ }\mathbf{a},-\text{ }\mathbf{a} \right),\left( \mathbf{0},\mathbf{0} \right),\left( \mathbf{a},\mathbf{b} \right)\] and \[\left( {{\mathbf{a}}^{\mathbf{2}}},\mathbf{ab} \right)\] are

A) vertices of the rectangle                 

B) vertices of the square

C) vertices of the parallelogram              

D) collinear

Correct Answer: D

Solution :

[d]    \[=a\times 0=0\]   [\[\therefore {{R}_{3}}\]and\[{{R}_{4}}\]be identical] Hence, the points \[\left( -\text{ }a,-\text{ }a \right),\left( 0,0 \right),\left( a,b \right)\] and \[\left( {{a}^{2}},ab \right)\] be collinear.