A) (a) 7
B) (b) 8
C) (c) 9
D) (d) 10
Correct Answer: C
Solution :
[c] \[\because y=5+4x-{{x}^{2}}\] \[\frac{dy}{dx}=4-2x\]For maximum & minimum value of y. \[\frac{dy}{dx}=0\Rightarrow 4-2x=0\] \[x=2\frac{{{d}^{2}}y}{d{{x}^{2}}}=-2\] Hence value of \[y=5+4\times 2-{{(2)}^{2}}\] \[=5+8-4=9.\]You need to login to perform this action.
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