A) \[\frac{1}{3}\]
B) \[\frac{1}{4}\]
C) \[\frac{1}{2}\]
D) \[\frac{2}{3}\]
Correct Answer: B
Solution :
[b] \[\because A\And B\]be mutually exclusive events \[\And S=A\cup B.\] \[\therefore ~P\left( A\cup B \right)=P\left( A \right)+P\left( B \right)\] \[\Rightarrow P\left( S \right)=\frac{1}{3}.P\left( B \right)+P\left( B \right)\] \[\Rightarrow 1=\frac{4}{3}.P(B)\] \[\Rightarrow P(B)=\frac{4}{3}\] \[\therefore p(A)=\frac{1}{3}.p(B)=\frac{1}{3}.\frac{1}{4}=\frac{1}{4}\] Hence, option [b] is correct.You need to login to perform this action.
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