A) 1
B) 2
C) 0
D) 3
Correct Answer: A
Solution :
[a] \[\because \]Let \[\alpha ,\alpha +1\]be the roots of equation \[{{x}^{2}}-bx+c=0\] \[\therefore \alpha +\alpha +1=b\] \[\alpha \left( \alpha +1 \right)=c\] \[\because {{b}^{2}}-4ac={{(2\alpha +1)}^{2}}-4.1.\alpha (\alpha +1)\] \[=4{{\alpha }^{2}}+4\alpha +1-4{{\alpha }^{2}}-4\alpha \] = 1 [Here\[a=1\]] Hence, option [a] is correct.You need to login to perform this action.
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