A) 1
B) \[-1\]
C) 0
D) 2
Correct Answer: B
Solution :
[b] \[\because \alpha \]be the comment roots of the given quadratic equation we have \[\therefore {{\alpha }^{2}}+a.\alpha +b=0\] ??..(1) \[\And {{\alpha }^{2}}+b.\alpha +a=0\] ?? (2) (1) ?(2), we have \[\alpha (a-b)+b-a=0\] \[\alpha (a-b)=\left( a-b \right)\] \[\therefore \alpha =1\] Putting these value in the given quadratic equation we have. \[{{1}^{2}}+\alpha .1+b=0\] \[\Rightarrow a+b=-1\] Hence option [b] is correct.You need to login to perform this action.
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