A) 3e
B) 2e
C) e
D) 5e
Correct Answer: C
Solution :
[c]\[1+\frac{3}{2}+\frac{5}{4}+\frac{7}{6}+......to\,\,\infty \] \[=1+\frac{2+1}{2}+\frac{4+1}{4}+\frac{6+1}{6}+......to\,\,\infty \] \[=1+\frac{1}{1}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}......to\,\infty ={{e}^{1}}=e\]Hence, option [c]is correct.You need to login to perform this action.
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