In given figure \[\Delta \]ABC is an isosceles triangle with AB = AC. |
Take a trace-copy of \[\Delta \]ABC and also name it as \[\Delta \]ACB. |
(a) State the three pairs of equal parts in \[\Delta \]ABC and \[\Delta \]ACB. |
(b) Is\[\Delta ABC\cong \Delta ACB\]? Why or why not? |
(c) Is \[\angle \]B = \[\angle \]C? |
Answer:
(a) In the given triangles DABC and DACB, AB = AC AC = AB \[\angle A=\angle A\] (b) As all the three corresponding sides of \[\Delta ABC\]and \[\Delta ACB\]are equal. Hence, by S.S.S. congruency \[\Delta ABC\cong \Delta ACB\] (c) By c.p.c.t., \[\angle B=\angle C\].
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