question_answer

Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonal is 8 cm long, find the length of the other diagonal.

Answer:

We have Area of rhombus = base \[\times \] altitude

\[=5\times 4.8\]

\[=\text{ }24\text{ }c{{m}^{2}}~~\]

Also,         Area of rhombus \[=\frac{1}{2}\,{{d}_{1}}.{{d}_{2}}\]

24                    \[=\frac{1}{2}\times 8\times {{d}_{2}}\]

\[\Rightarrow \,\,\,{{d}_{2}}\]      \[=\frac{24\times 2}{8}=6\] cm

\[\therefore \]      Area of rhombus \[=\text{ }24\text{ }{{m}^{2}}\]

Other diagonal of rhombus = 6 cm.