Answer:
We have \[\frac{16}{39}+\frac{9}{(-26)}=\frac{16}{39}+\frac{-9}{26}\] Now, the LCM of 39 and 26 is 78. \[\therefore \] Rewritine \[\frac{16}{39}\] and \[\frac{-9}{26}\] in such a manner they have the same denominator 78. \[\frac{16}{39}=\frac{16\times 2}{39\times 2}=\frac{32}{78}\] \[\frac{-9}{26}=\frac{-9\times 3}{26\times 3}=\frac{-27}{78}\] \[\frac{16}{39}+\frac{-9}{26}=\frac{32}{78}+\frac{(-27)}{78}\] \[=\frac{32+(-27)}{78}\] \[=\frac{32-27}{78}=\frac{5}{78}\]
You need to login to perform this action.
You will be redirected in
3 sec