question_answer

  The floor of a building is covered with 2760 tiles. Each of the tiles is in the shape of a parallelogram of altitude 3 cm and base 4.5 cm. Find the cost of polishing the tiles at the rate of Rs 20 per\[{{m}^{2}}\].

Answer:

Area of one tile (parallelogram shape) = base × height = 3 × 4.5 \[=13.5\text{ }c{{m}^{2}}\] Area of such 2760 tiles = 2760 × \[=13.5\text{ }c{{m}^{2}}\] \[=37,260\text{ }c{{m}^{2}}\] \[=3.726\text{ }{{m}^{2}}\] Cost of polishing = 3.726 × 20                                                                                                                = Rs 74.52.