Answer:
we have, \[\cos ({{\sec }^{-1}}x\,+\text{cose}{{\text{c}}^{-1}}x),\] \[|x|\,\,\ge 1\] \[\Rightarrow \] \[y=\cos \frac{\pi }{2}\] \[\left[ \because \,\,{{\sec }^{-1}}x+\text{cose}{{\text{c}}^{-1}}x=\frac{\pi }{2} \right]\] \[\Rightarrow \] y = 0 \[\therefore \] \[\frac{dy}{dx}=0\]
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