Answer:
Let x units of A and y units of B are produced. Then LPP is Maximise\[Z=100x+120y\]subject to the constraints \[x\ge 0,\,\,y\ge 0\] \[2x+3y\le 30\] And \[3x+y\le 17\] Plotting the graph of in equations we notice, shaded portion represents the optimum solution. Feasible points for maximum revenue are\[A\,\left( \frac{17}{3},\,\,0 \right),\]\[B\,(3,\,\,8)\]and\[C\,(0,\,\,10)\].
Revenue is maximum at\[B\,(3,\,\,8)\], i.e. \[x=3,\]\[y=8\]. Hence, 3 units of A and 8 units of B must be produced to get maximum revenue of Rs. 1260. Value The manufactures consider man and women equally efficient which helps the growth of women in the society. Corner points \[Z=100x+120y\] \[A\,\left( \frac{17}{3},\,\,0 \right)\] \[\frac{1700}{3}+0=566.67\] \[B\,(3,\,\,8)\] \[300+960=1260\](Maximum) \[C\,(0,\,\,10)\] \[0+1200=1200\]
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