Answer:
In the above figure, AB and CD are two poles whose heights are 9 m and 14 m respectively. AB = EC = 9 m And BD = 13 m DE = 14 - 9 = 5 m Now in right ABCDE, by Pythagoras \[B{{D}^{2}}-\text{ }B{{E}^{2}}+\text{ }D{{E}^{2}}\] \[{{13}^{2}}-\text{ }B{{E}^{2}}-\text{ }{{5}^{2}}\] \[B{{E}^{2}}\text{=}{{\left( 13 \right)}^{\text{2}}}\text{-}{{\left( 5 \right)}^{2}}\] = 169 - 25 \[B{{E}^{2}}-144\] \[BE=\sqrt{44}\] \[BE=12\text{ }m\], Hence, distance between their feet =12 m.
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