question_answer

  In the given figure, triangles \[\Delta \]ABC and \[\Delta \]BCD are right angled at A and D respectively. Prove that \[\Delta ABC\cong \Delta DCB\]. Is AB = DC? Give reason.

Answer:

In\[\Delta ABC\text{ }and\text{ }\Delta DCB\], AC = DB                      [given] ZBAC = ZCDB = 90°     [given] BC=BC                        [common] So by R.H.S. congruency we have \[\Delta ABC\cong \Delta DCB\] By c.p.c.t., AB = DC