question_answer

A container has 3 red balls, 6 white balls. If a ball is pulled without seeing them.

(a) What is the probability of getting a red ball?

(b) What is the probability of getting a white ball?

Answer:

Total no. of balls =3+6=9

(a) Probability of getting a red ball

=\[\frac{Total\text{ }No.\text{ }of\text{ }red\text{ }balls}{Total\text{ }No.\text{ }of\text{ }balls}\]

= \[\frac{3}{9}=\frac{1}{3}\]

(b) Probability of getting a white ball

=\[\frac{Total\text{ }No.\text{ }of\text{ }white\text{ }balls}{Total\text{ }No.\text{ }of\text{ }balls}\]

= \[\frac{6}{9}=\frac{2}{3}\]