(a) From the sum of 3xy + 11 and y 11, subtract 3x y 11. |
(b) From the sum of 4 + 3x and \[5-4x+2{{x}^{2}},\] subtract the sum of \[3{{x}^{2}}-5x\] and\[-{{x}^{2}}4-2x+5\]. |
Answer:
(a) The sum of 3x - y + 11 and - y -11 is given by (3x ? y + 11) + (-y - 11) = 3x - y+ 11-y - 11
= 3x - 2y
Now, we have to subtract 3x - y -11 from 3x - 2y. Required expression = (3x - 2y) - (3x -y-11)
= 3x - 2y - 3x + y + 11
=-y + 11
(b) The sum of 4 + 3x and \[5-4x+2{{x}^{2}}\] is given by
\[\left( 4+3x \right)+\left( 5-4x+2{{x}^{2}} \right)=4+3x+5-4x+2{{x}^{2}}\]
\[=9-x+2{{x}^{2}}\]
The sum of \[3{{x}^{2}}-5x\] and \[-\text{ }{{x}^{2}}+2x-t-5\] is given by
\[\left( 3{{x}^{2}}-5x \right)+\left( -{{x}^{2}}+2x+5 \right)\]
\[=\text{ }3{{x}^{2}}-5x-x2+2x+5\]
\[=\text{ }2{{x}^{2}}-3x+5\]
Now, we have to subtract 2x2 - 3x + 5 from
\[9-x+2{{x}^{2}}\]
\[\therefore \]Required expression\[=\left( 9-x+2{{x}^{2}} \right)-\]
\[\left( 2{{x}^{2}}-3x+5 \right)\]
\[=9-x+2{{x}^{2}}-2{{x}^{2}}+3x-5\]
= 2x + 4.
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