A container has 3 red balls, 6 white balls. If a ball is pulled without seeing them. |
(a) What is the probability of getting a red ball? |
(b) What is the probability of getting a white ball? |
Answer:
Total no. of balls =3+6=9 (a) Probability of getting a red ball =\[\frac{Total\text{ }No.\text{ }of\text{ }red\text{ }balls}{Total\text{ }No.\text{ }of\text{ }balls}\] = \[\frac{3}{9}=\frac{1}{3}\] (b) Probability of getting a white ball =\[\frac{Total\text{ }No.\text{ }of\text{ }white\text{ }balls}{Total\text{ }No.\text{ }of\text{ }balls}\] = \[\frac{6}{9}=\frac{2}{3}\]
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