Answer:
Let the number be 2x, 3x and 4x, then \[{{(2x)}^{3}}+\text{ }{{(3x)}^{3}}+\text{ }{{(4x)}^{3}}=0.334125\] \[8{{x}^{3}}+27{{x}^{3}}+64{{x}^{3}}=0.334125\] \[99{{x}^{3}}=\text{ }0.334125\] \[{{x}^{3}}=\frac{0.334125}{99}\] \[{{x}^{3}}=\text{ }0.003375\] \[{{x}^{3}}=\frac{3375}{1000000}\] \[x=\sqrt[3]{\frac{3375}{1000000}}\] \[=\frac{15}{100}\] = 0.15 Hence, the number are 0.3, 0.45 and 0.6.
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