Answer:
Area of the triangle ABC \[=\frac{1}{2}\times base\,\,\times \,\,Height\] \[=\frac{1}{2}\times AB\,\times \,\,BC\] \[=\frac{1}{2}\times 8\,\times \,\,12\] = 4 × 12 \[=48\,{{m}^{2}}\] Again, also area of ΔABC \[=\frac{1}{2}\times AC\times BD\] \[48=\frac{1}{2}\times 13\times BD\] D = 96 Thus, BD =\[\frac{96}{13}\]= 7.38 cm
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