Answer:
The greatest capacity of the required measure will be equal to the HCF of 120,180 and 240 L. Prime factorisation of 120,180 and 240
2 120 2 60 3 30 5 15 5 5 1
2 180 2 90 3 45 5 15 5 5 1
\[120=2\times 2\times 2\times 3\times 5\] \[180=2\times 2x\times 3\times 3\times 5\] \[240=2\times 2\times 2\times 2\times 3\times 5\] Common factors of 120, 180 and\[240=2\times 2\times 3\times 5=60\] Hence, greatest capacity of tin = 60 L. 2 240 2 120 2 60 3 30 5 15 5 5 1
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