Answer:
Katrina rode her bicycle in the morning\[=6\frac{1}{2}\text{km}\]\[=\frac{13}{2}\text{km}\] Katrina rode her bicycle in the evening\[=8\frac{3}{4}\text{km}\]\[=\frac{35}{4}\text{km}\] Hence, distance travelled by her altogether on that day \[=\frac{13}{2}+\frac{35}{4}\]\[=\frac{13\times 2}{2\times 2}+\frac{35}{4}\]\[=\frac{26}{4}+\frac{35}{4}\]\[=\frac{26+35}{4}=\frac{61}{4}\]\[=15\frac{1}{4}\text{km}\]
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