Answer:
Using the identity \[{{\left( a-b \right)}^{2}}={{a}^{2}}-2ab+{{b}^{2}},\] We have, \[\left( 3x-\frac{1}{3} \right)\left( 3x-\frac{1}{3} \right)={{\left( 3x-\frac{1}{3} \right)}^{2}}\] \[={{(3x)}^{2}}-2(3x)\left( \frac{1}{3} \right)+{{\left( \frac{1}{3} \right)}^{2}}\] \[=9{{x}^{2}}-2x+\frac{1}{9}.\]
You need to login to perform this action.
You will be redirected in
3 sec