Answer:
We have, A = B \[\Rightarrow \] \[\left[ \begin{matrix} a+4 & 3b \\ 8 & -\,6 \\ \end{matrix} \right]=\left[ \begin{matrix} 2a+2 & {{b}^{2}}+2 \\ 8 & {{b}^{2}}-5b \\ \end{matrix} \right]\] On equating the corresponding elements, we get \[a+4=2a+2\] ? (i) \[3b={{b}^{2}}+2\] ? (ii) and \[-\,6={{b}^{2}}-5b\] ? (iii) From Eq. (i), we get a = 2 and from Eqs. (ii) and (iii), we get \[3b=(5b-6)+2\] \[\Rightarrow \] \[-\,2b=-\,4\] \[\Rightarrow \] b = 2 Hence, the values of a and b are 2 and 2, respectively.
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