Find: |
(a) \[6\div 5\frac{1}{3}\] |
(b) \[7\div 2\frac{4}{7}\] |
Answer:
(a) We have \[6\div 5\frac{1}{3}=6\div \left( \frac{5\times 3\times 1}{3} \right)\] \[=6\div \left( \frac{15+1}{3} \right)=6\div \frac{16}{3}\] \[=6\times \frac{3}{16}\] \[\left[ \because reciprocal\text{ }of\frac{16}{3}is\frac{6}{16} \right]\] \[=\frac{18}{16}=\frac{9}{8}=1\frac{1}{8}\] [Dividing numerator and denominator by 2] (b) Do same as above. \[7\div 2\frac{4}{7}=2\frac{13}{18}\]
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