Answer:
DE - EA + AD - (8 + 5) cm - 13 cm DE is the radius of the circle. Also, DB is the radius of the circle. Next, AC == DB [Since diagonals of a rectangle are equal in length] Therefore, AC = 13 cm. From\[\Delta ADC,\text{ }D{{C}^{2}}\text{ }=A{{C}^{2}}-A{{D}^{2}}-{{13}^{2}}-{{5}^{2}}\] \[=169-25=144-{{12}^{2}}\] So, DC = 12 cm Thus, length of DC is 12 cm. Hence, perimeter of the rectangle ABCD =2(12 + 5) cm - 34 cm.
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