Answer:
Given, QP || RT \[\angle \]x = \[\angle \]PRT [since, alternate angles are equal] \[\angle \]x = 70° In \[\Delta \]PQR, \[x\text{ }+\text{ }30{}^\circ \text{ }+\text{ }y=\text{ }180{}^\circ \] [since, sum of all angles of a triangle is 180°] \[70{}^\circ \text{ }4-\text{ }30{}^\circ \text{ }+\text{ }y\text{ }=\text{ }180{}^\circ \] \[100{}^\circ +y=180{}^\circ \Rightarrow y\text{ }=180{}^\circ -100{}^\circ =80{}^\circ \]
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