Give a proper fraction: |
(a) Whose numerator is 5 and denominator is 7. |
(b) Whose denominator is 9 and numerator is 5. |
(c) Whose numerator and denominator add up to 10. How many fractions of this kind can you make? |
(d) Whose denominator is 4 more than the numerator. Give any five. How many more can you make? |
Answer:
(a) Numerator = 5, Denominator = 7 So, the fraction \[=\frac{5}{7}\] (b) Numerator = 5, Denominator = 9 So, the fraction \[=\frac{5}{9}\] (c) Possible pairs of numerator and denominator which add up to 10 are 0, 10; 1, 9; 2, 8; 3, 7; 4, 6 which give us proper fractions: \[\frac{0}{10},\frac{1}{9},\frac{2}{8},\frac{3}{7},\frac{4}{6}\] These are 5 in number. (d) 5 proper fractions in which denominator is 4 more than the numerator are \[\frac{0}{4},\frac{1}{5},\frac{2}{6},\frac{3}{7},\frac{5}{9}\] We can make an infinite number of proper fractions according to the given conditions.
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