Answer:
Let ABCD be a rectangle such that AB = 40 cm and AC = 41 cm. In right angled ΔABC, right angled at B, by Pythagoras theorem, we have x\[={{41}^{2}}{{40}^{2}}\] = (41 + 40) (41 ? 40) = 81 × 1 = 81 \[BC=\sqrt{81}=9cm,\] Now, perimeter of rectangle = 2(AB + BC) = 2(40 + 9) cm =2 × 49 cm = 98 cm
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