Answer:
Here, length \[3{{x}^{2}}-2\] breadth = 2x + 5 Area = (length) \[\times \] (breadth) \[=(3{{x}^{2}}-2)\times 2(2x+5)\] \[=3{{x}^{2}}(2x+5)+(-2)(2x+5)\] \[=6{{x}^{3}}+15{{x}^{2}}-4x-10\] Thus, the required area of the rectangle is \[6{{x}^{3}}-15{{x}^{2}}-4x-10\] sq. units.
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