Answer:
\[h=\frac{160}{800}=0.2\] So, required height = 0.2 m. Volume of water s= 160 m3 Area of rectangular field = 800 m2 Let h be the height of water level in the field. Now, volume of water = volume of cuboid formed on the field by water. 160 = Area of base \[\times \] height = 800 \[\times \] h
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