Answer:
In the given figure, it is given that AD = BC and AD||BC Now in ΔADC and ΔABC AD = BC [given] ∠DAC = ∠ACB 2 [As AD||BC and AC is transversal, ∠DAC and ∠ACB are alternate angles] AC = AC (common) So by S.A.S. congruency, we have ΔADC = ΔABC by c.p.c.t., AB = CD
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