Answer:
Here, l = 15 cm, b = 12 cm, h = 20 cm and r = 2.8 cm Surface area of cuboid = 2(lb + bh + hl) \[=2\left( 15\times 12+12\times 20+20\times 15 \right)\] \[=\text{ }2\left( 180+240+300 \right)\] \[=\text{ }2\times 720\] = 1440 cm2 Area of two holes \[=\text{ }27\pi {{r}^{2}}\] \[=2\times \frac{22}{7}\times 2.8\times 2.8\] = 49.28 cm2 So, Required area for paint = S.A. of cuboid - area of holes \[=\text{ }1440\text{ }-\text{ }49.28\] = 1390.72 cm2
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