question_answer

160 \[{{m}^{3}}\]of water is to be used to irrigate a rectangular field whose area is 800\[{{m}^{2}}\]. What will be the height of the water level in the field?

Answer:

Volume of water s= 160 m3

Area of rectangular field = 800 m2

Let h be the height of water level in the field.

Now,              volume of water = volume of cuboid formed on the field by water.

160 = Area of base \[\times \] height

= 800 \[\times \] h

\[h=\frac{160}{800}=0.2\]    So,   required height = 0.2 m.