Answer:
Let the breadth of the field be x metres. Then, length of the field be 2x metres. Therefore, area of the rectangular field = length \[\times \]breadth \[=\text{ }\left( 2x \right)\left( x \right)=\left( 2{{x}^{2}} \right)\text{ }{{m}^{2}}\] Given that area is 2450\[{{m}^{2}}\]. Therefore, \[2{{x}^{2}}=2450\] \[{{x}^{2}}=\frac{2450}{2}\] \[x=\sqrt{1225}\] or x = 35 m Hence, breadth = 35 m and length \[35\text{ }\times \text{ }2\] = 70 m Perimeter to the field \[=2\left( l+b \right)\] \[=2\left( 70+35 \right)\text{ }m\] \[=2\times 105\text{ }m\] = 210 m
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