Answer:
Let ABCD be the garden, and let PQRS be the external boundaries of the path. We have, AB = 90 m AD = 75 m PQ = (90 + 5 + 5) m =100 m and QR - (75 + 5 + 5) = 85 in Now, Area of the path = Area of PQRS -Area of ABCD \[=\left( 100\times 85-90\times 75 \right){{m}^{2}}\] \[=\left( 8500-6750 \right){{m}^{2}}\] \[=1750{{m}^{2}}\] Area of the garden = Area of ABCD \[=\left( 90\times 75 \right){{m}^{2}}-6750{{m}^{2}}\] \[=\frac{6750}{10000}\]hectare = 0.675
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