question_answer

Subtract the sum of (8a - \[6{{a}^{2}}\] + 9) and (-10a - 8 +\[8{{a}^{2}}\]) from -3.

Answer:

Sum of \[\left( 8a-6{{a}^{2}}+9 \right)\text{ }and\text{ }\left( -l0a-8+8{{a}^{2}} \right)\] \[=(8a-6{{a}^{2}}+9)+(-10a-8+8{{a}^{2}})\] \[=8a-6{{a}^{2}}+9-10a-8+8{{a}^{2}}\] \[=\left( 8{{a}^{2}}-6{{a}^{2}} \right)+\left( 8a-10a \right)+\left( 9-8 \right)\] \[-2{{a}^{2}}-2a+1\]                                                                                                                           Subtraction of.\[(2{{a}^{2}}-2a+1)\] from -3 \[=-3-\left( 2{{a}^{2}}-2a+1 \right)\] \[=-2{{a}^{2}}+2a-1-3\] \[=-2{{a}^{2}}+2a-4\]