Answer:
Let the six integers be 1, 2, - 2, 3, -3 and 6 Now, sum of above integers = 1 + 2 + (-2) + 3 + 3) + (- 3) + 6 we can arrange the numbers so that +ve integers and -ve integers are grouped together we have, i.e., \[=1+2+3+6+(-2)+(-3)\] \[=12-2-3\] Hence, required integers are 1, 2, -2, -3, 3 and 6. [Note: There are infinite combinations that exist]
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